Correct.
It can only condense the water that is in the air in the tank.
50 gallons is 6 cubic feet(close enough for math here.).
1 cubic foot of air at a standard temperature and pressure weighs approximately 0.08lbs
Max water a cubic foot of air can hold is one pound(a pint/16 ounces volume=16 ounces weight for water) per 500 cubic feet of air.
The most possible water that can be in your empty fuel tsnks air is
8cubic feet/500cubic feet= 1/60th+- of a pound.
0.25 ounces=6 teaspoons to an ounce...=1/2+ teaspoon MAX of water in your half full gas tanks atmosphere.
Punchline:
If your half tank of gas sucked the air to 0% humidity from 100% in your closed system You'd have 1/2 of a teaspoon of water added to 25 gallons of gas.
Closed system.
Leave the gas cap off to see different results.
Maybe 4 times worse for a total of a tablespoon of water added to your 25 gallons of fuel
Water is 8lbs+ per gallon.
(Thus My rounding of numbers due to 2, 6, 8,16, .08, 60, 1/60th, pints, ounces, pounds.)
It takes 500 cubic feet of air to hold a pound/pint of water at 60%(call it 50%for ease of remembrance) humidity.
That takes an empty 4500(call it 5,000 so its easy) gallon tank to have a pint/pound of atmospheric water. (that's 1:/60,000ish)
Bonus.
Open atmosphere burning a gallon of gas will/might/can generate 6+(maybe 8) gallons of water.
How?
(My math is from memory of things I don't particularly care about. I could be off on occasion, but nothing that changes the gist.)
And
I am often wrong.
And why did everyone join the
'I think'
Instead of thinking?
The op said nothing involving an expert opinion.
Wild guess gone wild.