Quote:
Originally Posted by Bob Denman
Thanks for saying what you did: now show me something!
So how do you figure the percentage of reduction in this situation?
You go from 120 degrees: to 108 degrees?
Let's use Fahrenheit as the scale...
What's the percentage?
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First, you don't get to make the rules of how it's done, otherwise I'd be just as wrong as you. I can see you're setting it up as a test so when I give you the answer you expect, you'll then change it to Celsius and the percentage temperature drop will be different, right? Sorry, but I'm not that naive.
To do it correctly, temperatures have to be in an absolute zero scale, so in this case it's easier to use Rankine.
108 F is 568 R
120 F is 580 R
568/580 = 97.9%
Roughly 2 percent decrease in temperature.
Bob, try the same converting to Celsius using Kelvin absolute scale and you'll get same answer.
As stated before, 10% decline in real life would be around 60 degrees F, which seems too high to me, and why I questioned it.