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Old 02-23-2018, 01:47 PM   #41
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Quote:
Originally Posted by Bob Denman View Post
You can't really speak about percentages; when discussing temperatures.

You're dealing with temperature ranges that can go below zero. (Even thought that is extremely unlikely!)
It's much better to just mention the decrease in the amount of degrees...
Which I'm kind of sure that the poster of the information may have meant to do...
Yes you can. It's done all the time, but you have to know what you're doing which you obviously don't. I don't mean to sound rude but your knowledge on this subject is too limited to understand that it can be done. And more importantly, it serves a purpose when evaluating engine performance.

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Old 02-23-2018, 03:26 PM   #42
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Thanks for saying what you did: now show me something!

So how do you figure the percentage of reduction in this situation?
You go from 120 degrees: to 108 degrees?
Let's use Fahrenheit as the scale...
What's the percentage?
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Old 02-23-2018, 04:20 PM   #43
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Originally Posted by Bob Denman View Post
Thanks for saying what you did: now show me something!

So how do you figure the percentage of reduction in this situation?
You go from 120 degrees: to 108 degrees?
Let's use Fahrenheit as the scale...
What's the percentage?

First, you don't get to make the rules of how it's done, otherwise I'd be just as wrong as you. I can see you're setting it up as a test so when I give you the answer you expect, you'll then change it to Celsius and the percentage temperature drop will be different, right? Sorry, but I'm not that naive.

To do it correctly, temperatures have to be in an absolute zero scale, so in this case it's easier to use Rankine.

108 F is 568 R

120 F is 580 R

568/580 = 97.9%

Roughly 2 percent decrease in temperature.


Bob, try the same converting to Celsius using Kelvin absolute scale and you'll get same answer.


As stated before, 10% decline in real life would be around 60 degrees F, which seems too high to me, and why I questioned it.
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Old 02-23-2018, 04:51 PM   #44
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We DO have a winner here!!
I guess that neither of us is quite as dumb as the other guy thinks!
2.07% or so...

And congratulations on being able to find "Ab-Z" for the problem.
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Old 02-23-2018, 04:59 PM   #45
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Tell the truth: did you actually think that I'm "just another pretty face"?

http://www.thorforums.com/forums/att...1&d=1519410954

Not everybody digs Math: it just happens to put up with me pretty well.
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Old 02-23-2018, 08:34 PM   #46
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How can you get a 10% temperature reduction unless comparing to an OEM system that wasn't operating correctly?

Normal intake temperatures I'm familiar with aren't high enough to allow that much reduction.
Actually I miss spoke, was thinking about the fuel additive I use that improved MPG by 10% on a round trip to Colorado, about 1700 miles. The CAI actually lowered temps to about ambient on the open road, stop and go is another story as I am not getting as much air through the system. The 5% MPG increase for the CIA is more an estimate based on much shorter distances so it could be off. I used the Volant but I don't see one listed for the F-53.

Sorry for the misleading post.

Volant Cold Air Intakes - Read Reviews & FREE SHIPPING!
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Old 02-23-2018, 09:13 PM   #47
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No problem, and thanks for reply Bruce.

I was just curious because I still recall the theory (ICE at university level) behind colder and therefore denser air at intake of a gasoline engine, and there is no doubt the engine will put out more power at full throttle, and also be slightly more efficient as well. However, at partial load which is the way we drive most of the time, any improvement in density due to colder air will be partly offset by the throttle requiring to be less open to maintain same horsepower. An exception would be if the colder air intake allowed the vehicle to hold a taller gear (greater max torque available), but that's highly unlikely for any amount of time that would affect fuel economy over an entire trip. These motorhomes are designed with ability to hold top gear the vast majority of the time, so excluding a few hills it won't make much difference. I'm not saying it won't help, just not very much beyond what Ford provides.

I'm certain Ford engineers know this far better than we do, and if there was significant improvement to be had, they'd be all over it. The differential cost must be minimal if it means more power and fuel economy.
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Old 02-23-2018, 10:55 PM   #48
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I agree: thanks for coming back in on this!
Colder air (by itself) will often cause a drop in fuel economy on fuel injected vehicles.
Colder air is denser. You're literally getting more air into the engine. .
In order to keep the a/f mixture just right (Probably for emissions requirements); the amount of fuel charge will need to be increased.
So the system stuffs more fuel into the injectors.
....Which DOES help you make more power.
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